by selling two transistors for RS 480 each a man loses 205 on one and gains 20% on the other. how much percent did he gain or lose on the whole?
Answers
Answer:
answer
Step-by-step explanation:
Let CP
1
& CP
2
be the cost price of 1
st
transistors and 2
nd
transistors respectively
selling price of each transistors, SP
1
=RS600
Gain of one transistors = 20%
⇒
CP
1
SP
1
−CP
1
×100=20.
⇒
CP
1
600−CP
1
×100=20.
⇒600−CP
1
=
100
20
CP
1
⇒600=
100
20
CP
1
+CP
1
⇒
100
120
CP
1
=600
⇒CP
1
=
120
600×100
⇒CP
1
=Rs500
and loss of other transistors = 20 %
⇒
CP
1
CP
2
−SP
1
×100=20
⇒CP
2
−600=
100
20
CP
2
⇒CP
2
100
−20
CP
2
=600
⇒
100
80
CP
2
=600
⇒CP
2
=
80
600×100
=RS 750
cost price of 1
st
transistors = Rs 1350
Cost price of 2
nd
transistors = Rs 750.
Total cost price ,CP = Rs (600+750) = 1350
Total selling price SP = Rs (600+600) = Rs 1200.
loss on the whole =
CP
CP−SP
×100
1350
1350−1200
×100
1350
150
×100
= 11.11 % (approx.)