Math, asked by Suriharshi, 7 months ago

By selling two transistors for Rs600 each, a shopkeeper gains 20%on one transistor and loses 20% on the other. Find:

1) C.P of each transistor

2) Total CP and total SP

3) Profit or loss on the whole​

Answers

Answered by aarav511
1

Step-by-step explanation:

CP of first transistor =500

CP of second transistor=₹750

Answered by VivekNNV
1

Answer:

1) C.P of each transistor = Rs. 500 and Rs. 750

2) Total CP = Rs. 1250 and total SP = Rs. 1200

3) Loss on whole transaction (4% loss)

Step-by-step explanation:

Selling two transistors each at Rs. 600. So, total Selling Price is Rs. 1200

First Transaction- 20% gain by selling at Rs. 600

120% of CP1 = 600

(120/100) × CP1 =600

CP1 = Rs. 500

Second Transaction - 20% loss by selling at Rs. 600

80% of CP2 = 600

(80/100) × CP2 = 600

CP2 = Rs. 750

So, total CP's = 500+750 = Rs. 1250

So, he bought two transistors at Rs. 1250 and sell it for Rs. 1200. So, clearly it is Loss on whole transaction.

Loss percentage:

1250 = 100%

1200 = ? %

= (1200×100) ÷ 1250

= 96%

So, (100-96) 4% loss.

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