Math, asked by poojabhatnagar3, 3 months ago

by selling45 oranges for 160, a woman loses 20%. how many oranges should she sell for 112 to gain 20% on the whole. ​

Answers

Answered by Anonymous
5

Step-by-step explanation:

Let CP be Rs x

case of loss,

SP of 1 orange = Rs 160/45

Loss = 20%

⇒SP = CP - Loss

        = x - 20% of x = x - 0.2x = 0.8x

⇒160/45 = 0.8x  

⇒x = Rs 40/9

case of gain,

Let the number of orange be y

SP of 1 orange = Rs 112/y

SP = CP + gain

     = x + 20% of x = x +0.2x = 1.2x = 1.2×(40/9)

⇒112/y = 1.2×(40/9)

⇒y = 21

so, 21 oranges should she sell for rupees 112 to gain 20% on the whole.

Answered by bharathrahul15
0

Step-by-step explanation:

By selling 45 lemons for Rs 40, a man loses 20%. How many should he sell for Rs 24 to gain 20% in the transaction ?

A) 16

B) 18

C) 20

D) 22

Answer: B) 18

Explanation:

Let S.P. of 45 lemons be Rs. x.

Then, 80 : 40 = 120 : x or x = 40×12080= 60

For Rs.60, lemons sold = 45

For Rs.24, lemons sold =4560×24= 18.

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