Question

by solve 2sin inverse of x=cos inverse of x ​

Answer 1

· Let sin−1x=θ , so that, x=sinθ,|x|≤1,θ∈[−π2,π2]. ... Value =cos (2sin−1x)=cos2θ=1−2sin2θ

Answer 2

Step-by-step explanation:

here your answer ......

2sin^-1 x^= cos ^-1 x.

but we know .....

sin^-1 x + cos ^-1 x = pi/2.

so. .... cos ^-1 x =pi/2-sin^-1x.

so...

2sin^-1x =pi/2-sin^-1x.

3sin^-1 x= pi/2 .

sin^-1x =pi/6.

x=sin(pi/6)

. x= root(3)/2.

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