by solving these equations..
.find a, b and c
a+b+c=84
30a+50b+70c=4120
3a-4b=0
Answers
Answer:
a = 32,b=24 and c= 28
Step-by-step explanation:
1st take the equation
a+b+c= 84
c=84-a-b(remember this)
now take the equation
30a+50b+70c=4120
solve here for c
it will be
30a +50b +70 (84-a-b)=4120
u will get
30a + 50b+ 5880-70a-70b=4120
-40a-20b= -1760
-(40a + 20b)= - 1760
minus cancels
therefore 40a + 20b =1760
divide it by 20 bcz 20 is common in all.numbers
soo the equation will be
2a+b=88-------1st equation
3a-4b=0 ------2nd equation as it is given
do simultaneous equation
2a+b=88-----×4
3a-4b=0
------------------
8a+4b=352
3a-4b=0
(here +4b and -4b gets cancelled )
---------------------
u will get
11a=372
a=32//
2a+b=88(here substitute the a value to find b)
u will get b as 24 and to get c
substitute a and b values in the equation a+b+c=84
sooo 32+24+c = 84
therefore c = 28
i really enjoyed doing this sum
My name is Nishanya and i m 15 hope u understood my answer
Answer:
Shehnaaz kiran da ki haal Aa koi nvi tzi.... Deepika mam di smj aa jndi ?