Question

by splitting method factorise the polynomial, f(x)= 2x^2-4x+5​

Answer 1

Answer:

$2x {}^{2} - 4x + 5 \\ vertex = \frac{ - b}{2a} = \frac{4}{4} = 1 \\ f(1) = 2(1) {}^{2} - 4(1) + 5 \\ 2 - 4 + 5 \\ - 2 + 5 \\ 3 \\ roots = \frac{ - b ( + - ) \sqrt{b {}^{2} - 4ac} }{2a} - \frac{4( + - ) \sqrt{16 - 2 \times 2 \times 5} }{2a} \\ therefore \: imaginary \: roots$

Step-by-step explanation:

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