Question

By splitting the middle
term
Find the zeroes of x2-7x-60

HELP ME FIND THE ANS FOR THIS WITH STEP BY STEP EXPLANATION​

Answer 1

Answer:

Step-1 : Multiply the coefficient of the first term by the constant 1 • -60 = -60

Step-2 : Find two factors of -60 whose sum equals the coefficient of the middle term, which is 7 .

-60 + 1 = -59

-30 + 2 = -28

-20 + 3 = -17

-15 + 4 = -11

-12 + 5 = -7

-10 + 6 = -4

-6 + 10 = 4

-5 + 12 = 7 That's it

Answer 2

Answer:

The zeroes are -5 and 12.

Step-by-step explanation:

x^2-7x-60

x^2-12x+5x-60

{ -7x = -12x +5x }

x (x-12) + 5 (x-12)

{ Taking (x-12) common }

which comes out to be...

(x+5).(x-12)

Now, equating these with zero...

• x+5 = 0.
• x = -5.

Again...

• x-12 = 0.
• x = 12.

Hence the zeroes are : -5 and 12.