by substitution Method
3x-5y=4
9x=2y+7
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3x-5y=4 ----------(1)
9x-2y=7 -----------(2)
from equation (1)
x=( 4+5y)/3
substitute x=(4+5y)/3 in equation (2)
9(4+5y)/3-2y=7
12+15y-2y=7
12+13y=7
13y=7-12
13y=-5
y=-5/13 ----------(3)
substitute -5/13 in equation (1)
3x-5(-5/13)=4
3x+25/13=4
(39x+25)/13=4
39x+25=52
39x=52-25
39x=27
x=27/39=9/13 -------------(4)
therefore,
from equation (3) and (4) we get x=9/13 and y=-5/13
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