Question

by substitution method find 2x+3y=8 and 4x+6y=7

Answer 1

No solution is ur answer

Answer 2

Hello Dear.

Let 2x + 3y = 8 be eq(i) and 4x + 6y = 7 be eq(ii).

Now, From eq(i),
2x + 3y = 8
2x = 8 - 3y
x = (8 - 3y)/2  

Putting the Value of x in eq(ii),

4x + 6y = 7
4(8 - 3y)/2 + 6y = 7
2(8 - 3y) + 6y = 7
16 - 6y + 6y = 7
16 = 7
16 - 7 = 0
 9 = 0

That is not true.

From the Calculations, We can see that the Equations has no solution.


Hope it helps.