By substitution method find 9x-4y=2000 and 7x-3y=2000
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10
Answer :
Given,
9x - 4y = 2000 ...(i)
7x - 3y = 2000 ...(ii)
From (i), we get
9x = 2000 + 4y
⇒ x = (2000 + 4y)/9
Now, substituting x = (2000 + 4y)/9 in (ii), we get
7 × (2000 + 4y)/9 - 3y = 2000
⇒ (14000 + 28y)/9 - 3y = 2000
⇒ (14000 + 28y - 27y)/9 = 2000
⇒ 14000 + y = 18000
⇒ y = 18000 - 14000
⇒ y = 4000
Now,
x = (2000 + 4 × 4000)/9
= (2000 + 16000)/9
= 18000/9
= 2000
Therefore, the required solution is
x = 2000, y = 4000
#MarkAsBrainliest
Given,
9x - 4y = 2000 ...(i)
7x - 3y = 2000 ...(ii)
From (i), we get
9x = 2000 + 4y
⇒ x = (2000 + 4y)/9
Now, substituting x = (2000 + 4y)/9 in (ii), we get
7 × (2000 + 4y)/9 - 3y = 2000
⇒ (14000 + 28y)/9 - 3y = 2000
⇒ (14000 + 28y - 27y)/9 = 2000
⇒ 14000 + y = 18000
⇒ y = 18000 - 14000
⇒ y = 4000
Now,
x = (2000 + 4 × 4000)/9
= (2000 + 16000)/9
= 18000/9
= 2000
Therefore, the required solution is
x = 2000, y = 4000
#MarkAsBrainliest
Answered by
0
Answer:
it is done by using substitution, elimination aur cross multiplication method
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