Question

By substitution method solve
1. s-t =3, s/3+t/2=6

Answer 1

From 1 we get
s = t + 3
Putting in 2 we get
(t+3)/3 + t/2 = 6
(5t+6)/6 = 6
5t+6 = 36
5t = 30
Therefore t = 6
And s = 9
Hope it helps.....plz mark brainliest.....

Answer 2

Hi there !!

s - t = 3

$\frac{s}{3} + \frac{t}{2} = 6$          ------> [1]

s = t + 3           -----> [2]

put this value in equation [1] :-

$\frac{t + 3}{3} + \frac{t}{2}$ = 6

lcm of 2 and 3 is 6 :-
[tex] \frac{2t + 6}{6} + \frac{3t}{6} \\ [/tex] = 6


$\frac{5t+6}{6} = 6$

5t + 6 = 36

5t = 30

t = 30/5

t = 6

put this value of t in equation [2] ,

s = t + 3
s = 6 + 3
s = 9

hence ,

s = 9 , t = 3