By substitution method solve : x/3 + y/4 =6 , x/6 + y/2 = 6
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1) (4x+3y)/12=6
4x+3y=6*12
4x+3y=72
2)2x+6y/12=6
2x+6y=72
from1)
4x+3y=72
x=72-3y/4
substitute in 2)
2x+6y=72
2(72-3y/4)+6y=72
72-3y/2+6y=72
72-3y+12y/2=72
72-3y+12y=72*2
9y=36-72
9y= -36
y=-36/9
y= -4
substitute in 1)
4x+3y=72
4x+3(-4)=72
4x-12=72
4x=72+12
4x=84
x=84/4
x=21
I hope you understand
x=21,y= -4
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