Math, asked by Shuyeb4544, 9 months ago

By taking some negative integers, show that the product of an even number of negative integers is positive.

Answers

Answered by SwaggerGabru
1

Answer:

the inverse of 3 is -3, and the inverse of -3 is 3.

the inverse of 3 is -3, and the inverse of -3 is 3.Note that when you take the inverse of an inverse you get the same number back again: "-(-3)" means "the inverse of -3", which is 3 (because 3 is the number which, when added to -3, gives zero). To put it another way, if you change sign twice, you get back to the original sign.

the inverse of 3 is -3, and the inverse of -3 is 3.Note that when you take the inverse of an inverse you get the same number back again: "-(-3)" means "the inverse of -3", which is 3 (because 3 is the number which, when added to -3, gives zero). To put it another way, if you change sign twice, you get back to the original sign.Now, any time you change the sign of one of the factors in a product, you change the sign of the product:

the inverse of 3 is -3, and the inverse of -3 is 3.Note that when you take the inverse of an inverse you get the same number back again: "-(-3)" means "the inverse of -3", which is 3 (because 3 is the number which, when added to -3, gives zero). To put it another way, if you change sign twice, you get back to the original sign.Now, any time you change the sign of one of the factors in a product, you change the sign of the product:(-something) × (something else) is the inverse of (something) × (something else), because when you add them (and use the fact that multiplication needs to distribute over addition), you get zero.

Answered by bhanuprakashreddy23
0

Answer:

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Step-by-step explanation:

  • If there are an even number of negatives, the result is positive. If there are an odd number of negatives, the result is negative. Division can be rewritten as multiplication, by using the reciprocal or multiplicative inverse of the divisor.
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