Question

By taking the values of a, b and c as 20, -4 and 2 respectively verify that:
a÷(b+c)#(a÷b)+(a÷c)
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Answer 1

Answer:

Step-by-step explanation:

a÷(b+c)#(a÷b+(a÷c)

20÷(-4+2)#(20÷-4)+(20÷2)

20÷-2#-5+10

-10#-5

Hence proved.

Answer 2

Answer:

by simply putting the value and using BODMAS we can verify it.

Step-by-step explanation:

a=20, b=-4, c=2

a÷(b+c)=20÷(-4+2)

first we need to solve term in bracket

a÷(b+c)=20÷(-2)

a÷(b+c)=-10.............(1)

Now solve Right hand side

(a÷b)+(a÷c)=(20÷-4)+(20÷2)

(a÷b)+(a÷c)=(-5)+(10)

(a÷b)+(a÷c)=-5+10

(a÷b)+(a÷c)=5.....................(2)

From (1) & (2)

a÷(b+c) ≠ (a÷b)+(a÷c)