Question

by taking x=-2/3,y=5/9,z=-1/6, verify (x+y)÷z=(x÷z)+(y÷z)​

Answer 1

Step-by-step explanation:

$x=\frac{-2}{3}$

$y=\frac{5}{9}$

$z=\frac{-1}{6}$

$\frac{(x+y)}{z} =\frac{\frac{-2}{3}+\frac{5}{9} }{\frac{-1}{6} }$

$\frac{-2}{3} +\frac{5}{9} =\frac{-6+5}{9}$  (Take LCM as 9)

=$\frac{-1}{9}$

$\frac{-1}{9}$÷$\frac{-1}{6}$=$\frac{-1}{9}$×$\frac{6}{-1}$=$\frac{6}{9}$    (Minus sign will be cancelled)

6/9 will be simplified to 2/3.

So, (x+y)/z=2/3

(x/z)+(y/z)= x/z +y/z = (x+y)/z

Hence verified .

Hope this helps you.

Answer 2

Refer to the attachment

Hope it will help you a lot✌️✌️✌️✌️