By taking x = - 5/3, y = 2/7 and t = - 1/4 v erify that:- x/(y-z)≠(x/ y)-(x/ z)
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Answer:
I think in the question its not 't' its 'z'.
Step-by-step explanation:
According to the question we have x= -5/3,y=2/7,z= -1/4.
Now by taking LHS=x/(y-z)
-5/3/(2/7-(-1/4))=-5/3÷(2/7+1/4)= -28/9
so the value of LHS is -28/9
RHS=(x/y)-(x/z)
(-5/3÷(2/7))-(-5/3÷-1/4)= -35/3
LHS= -28/9
RHS= -35/3
So, LHS≠RHS
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