Question

by the method of substitution

Answer 1

Hey friend!!
We need two equations to solve them by substitution method..

Answer 2

Your Question:

$p(x+y)=q(x-y)=2pq$

Answer:

i.e.,

    $p(x+y) =2pq .......(i)\\q(x-y)=2pq ........(ii)$      

i.e.,

In (i),

           $(x+y)= 2q......(iii)$

           $(x-y)=2p......(iv)$

In (iv),

$x=2p+y.......(v)$

Substituting value of x in (iii),

$=>2p+y+y=2q\\=>2p+2y=2q\\=>p+y=q\\=>y=q-p$

Substituting value of y in (iv),

$=>x-(q-p)=2p\\=> x=2p+(q-p)\\=>x=2p+q-p\\=>x=q+p$

Therefore, x = q + p and y = q - p

Hope this answer helps you ^_^ !