Question

By transformation formula

Factorise
sec4∅-sec2∅=2​

Answer 1

Step-by-step explanation:

see the attachment......

Answer 2

SOLUTION

$= > sec {}^{4} \theta - sec {}^{2} \theta - 2 = 0 \\ = > sec {}^{4} \theta - 2 {sec}^{2} \theta + sec {}^{2} \theta - 2 = 0 \\ = > {sec}^{2} \theta( {sec}^{2} \theta - 2) + 1( {sec}^{2} \theta - 2) = 0 \\ = > ( {sec}^{2} \theta - 2)( { sec}^{2} \theta + 1) = 0 \\ = >sec \theta = </u><u>±</u><u>\sqrt{2} \: \: \:</u><u>±</u><u> i \: but \: imaginary \: is \: not \: possible \: so \\ = > sec = </u><u>±</u><u>\sqrt{2} \\ = > here \: \theta = 45 \degree \: \: \: or \: \: 135 \degree$

hope it helps ☺️