By translating the axes the equation ty – 27 – 3y – 4 = 0 has changed to XY = k then
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Suppose the origin is shifted to (α,β).
Then x−α=X
and y−β=Y
Therefore x=X+α
∴y=Y+β
Hence, xy−2x−3y−4=0
(X+α)(Y+β)−2(x+α)−3(Y+β)−4=0
⇒XY+βX+αY+αβ−2X−2α−3Y−3β−4=0
⇒XY+X(β−2)+Y(α−3)+αβ−2α−3β−4=0
To make the linear terms disappear.
⇒β−2=0
⇒α−3=0
Hence, (α,β)=(3,2)
Thus the axes have to be translated along (3,2).
On substituting, we get
XY+6−2(3)−3(2)−4=0
⇒XY+6−6−6−4=0
⇒XY=10
Hence, k=10
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