by using appropriate identify , factorise the following
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Step-by-step explanation:
1)125a^3+8b^3
=(5a)^3+(2b)^3
=(5a+2b)[(5a)^2+(2b)^2-5a*2b]
=(5a+2b) [25a^2+4b^2-10ab]
2)x^3+(y+z)^3
=(x+y+z)[x^2+(y+z)^2-x*(y+z)]
=(x+y+z)[x^2+(y^2+2yz+z^2)-xy-xz]
=(x+y+z)[x^2+y^2+z^2+2yz-xy-xz]
3)x^3-64y^3
=(x)^3-(4y)^3
=(x-4y)[x^2+16y^2+4xy]
4)x^3-(y-z)^3
=[x-(y-z)] [x^2+(y-z)^2+x(y-z)]
=(x-y+z)[x^2+(y^2-2yz+z^2)+xy-xz]
=(x-y+z)[x^2+y^2+z^2-2yz+xy-xz]
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