by using binomial theorem expand f(1-x+x^2)^4
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1+x+x2)3=1+3x+6x2+7x3+6 x4+3x5+x6 ... I don't think you do use the binomial theorem for this one, since (1+x+x2) is ...
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Answer:
Use a variant of Pascal's triangle to find:
(1+x+x2)3=1+3x+6x2+7x3+6x4+3x5+x6
Explanation:
This is a power of a trinomial, not a binomial so the binomial theorem does not help much.
However, note that 1,x,x2 are in geometric progression, so we can use a variant of Pascal's triangle to find the coefficients we want. Each term in this variant is the sum of the three terms above it, rather than two...
00000000001
00000001001001
00001002003002001
01003006007006003001
Hence we find:
(1+x+x2)3=1+3x+6x2+7x3+6x4+3x5+x6
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