by using completing square method solve the following equation
16x square - 24x - 13 = 0
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1
hope this helps u.....
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khushu18:
thanks yrr bt mujhe 4th step samajh ni aaya.... 1/2 se dono seide multiply.. kyun
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16x^2-24x=13
(4x)^2-2*4x*3+3^2=13+3^2
(4x-3)^2=13+9
(4x-3)^2=22
therefore
4x-3 = +or -root22
4x=3+ or -root22
x= (3+root22)/4 or x=(3-root22)/4
(4x)^2-2*4x*3+3^2=13+3^2
(4x-3)^2=13+9
(4x-3)^2=22
therefore
4x-3 = +or -root22
4x=3+ or -root22
x= (3+root22)/4 or x=(3-root22)/4
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