By using division algorithm. find the largest number which divides 969 and 2059, remainders obtained are 9 and 11
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let the number which divides 969 and 2059 be n
Since the number 969 and 2059 leaves remainder of 9 and 11 respectively
So,
(969 - 9) = 960 {multiple of n}
(2059 - 11) = 2048 {multiple of n}
Now, using Euclids division algorithm:
Let, a = 2047 and b = 960
a = bq + r, where 0 ≤ r ≤ b
=> 2048 = 960 × 2 + 128
=> 960 = 128 × 7 + 64
=> 128 = 64 × 2 + 0
=> HCF(2047, 960) = 64
So, the largest number that divides 969, 2059 and leaves 9 and 11 as remainder is 64
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