Question

By using duitable identies find 98*99

Answer 1

Answer:

9702

Step-by-step explanation:

98×99 can be written as (100-2)(100-1)

The identity to be used is [(x+a)(x+b)=x²+(a+b)x+ab]

So replacing the values,

=[100²+(-2+(-1))100+(-2×(-1)) ]

=10000+(-2-1)100+2

=10000-300+2

=9702

This is your answer. Hope I helped.