Question

By using elimination method solve x+¥=5 and 2x-3¥=7

Answer 1

Answer:

x+y=5-(I)

2x-3y=7-(ii)

(I)*3+(ii)

3x+3y=15

2x-3y=7

x=22/5

y=3/5

Answer 2

$x + y = 5 - - - - (i) \\ 2x - 3y = 7 - - - - (ii) \\ by \: elimination \: method \: we \: get \\ \: \: x \: + \: \: y = 5 \\ 2x - 3y = \: 7 \\ ( - )( + ) \: \: \: \: \: ( - ) \\ - - - - - - - \\ - x + 4y = - 2$