By using Euclids algorithm find the hcf of 4216 and 1240
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USE FORMULAE
P=QX+R WHERE P ISTHE BIGGER NUMBER BETWEEN TWO GIVEN AND Q IS THE SMALLER ONE
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Answer:
The required answer is 248.
Step-by-step explanation:
4216 = 2 x2 x 2 x 17 x 31
1240 = 2 x2 x2x5x 31
HCF = 2x 2 x 2 x 31 = 248
HOPE IT HELPS YOU DEAR..
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