By using Euclids algorithm find the hcf of 4216 and 1240
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Solution:-
The required answer is 248
=> 4216 = 2 x2 x 2 x 17 x 31
=> 1240 = 2 x2 x2x5x 31
=> HCF = 2x 2 x 2 x 31 = 24+8
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