by using identities solve the question. (√2x+√3y+z/√6) ka square
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Answer:
here is the answer
Step-by-step explanation:
we will use here the( a+b+c)2 formula.
According to it a2+b2+c2+2(ab+bc+ac)
So, 4x2+3y2+z2/ 6 cause root and 2 gets cancelled
Next 4x2+3y2+z2/6 +2( 4x2.3y2+3y2.z2/6+4x2.z2/6)
now what is inside the bracket that we have to multiply and can cancel some terms.
After doing that ... 4x2+3y2+z2/6+2(12x2y2+ y2z2/2 + 2 x2z2/3)
then just multiply each term by 2and get the answer.
Answer is 4x2+3y2+z2/6+24x2y2 + y2z2 + 4x2z2/3
Hope it helps you
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