Question

By using identity evaluate (ab + bc)² – 2ab²c.
fast plzzzzz

Answer 1

Answer:

a^2b^2+b^2c^2

Step-by-step explanation:

(ab+bc) ^2-2ab^2c

using (a+b) ^2=a^2+b^2+2ab

a^2b^2+b^2c^2+2ab^2c-2ab^2c

a^2b^2+b^2c^2