Question

by using method elimination by equating any one coefficient 4x+2y=-3;x+5y=4​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

) 3x−4y=7;5x+2y=3

3x−4y=7⇒ 3x−4y=7

2(5x+2y=3)⇒ 10x+4y=6

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13x+0=13

x=1 ⇒ 5+2y=3⇒ y=−1

∴ (x,y)=(1,−1)

(ii) 5x+7y=17;3x−2y=4

3(5x+7y=17)⇒15x+21y=51

5(3x−2y=4)⇒15x−10y=20

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31y=31⇒ y=1⇒ 3(x)−2=4⇒ x=2

∴ (x,y)=(2,1)

(iii) x−2y=−10;3x−5y=−12

3(x−2y=−10)⇒ 3x−6y=−30

3x−5y=−12

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−x=18⇒x=18

18−2y=−10⇒ y=14

∴ (x,y)=(18,14)

(iv) 4x+y=34;x+4y=16

4x+y=34⇒ 4x+y=34

4(x+4y=16)⇒ 4x+16y=64

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−15y=−30

⇒ y=2

4x+2=34

⇒ x=8

⇒ (x,y)=(8,2)

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