Question

by using method of first principle find derivative with respect to x log(2x+1)at x=2​

Answer 1

Answer:

(4/5) + log5

Step-by-step explanation:

-->x*d(log(2x+1))/dx + log(2x+1)*d(x)/dx

-->x*((1/(2x+1))*2) + log(2x+1)*1

substituting x = 2

-->2*((1/(2*2+1))*2) + log(2*2+1)

-->(4/5) + log5

-->0.8 + 0.69

-->1.49

(log5=0.69)