Question

by using properties prove that​

Answer 1

Step-by-step explanation:

=(b+c)((c+a*a+b - bc) -a(b*a+b-bc) +a(bc-c(c+a))

= (b+c)(ac+a²+bc+ab-bc) -a(ab+b²-bc) +a(bc-c²-ac)

=(b+c)(ac+a²+ab)-a(ab+b²-bc)+a(bc-c²-ac) =abc+a²b+ab²+ac²+a²c+abc-a²b-ab²+abc+abc-ac²-a²c

= 4abc