by using quardatric formula show that x-2y=8 and5x-10y=10
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The given system of equations is:
x – 2y – 8 = 0
5x – 10y – 10 =
The above equations are of the form
a1 x + b1 y − c1 = 0
a2 x + b2 y − c2 = 0
Here, a1 = 1, b1 = -2, c1 = −8
a2 = 5, b2 = -10, c2 = −10
So according to the question, we get
a1/a2 = 1/5
b1/b2 = −2/−10 = 1/5 and,
c1/c2 = −8/−10 = 4/5
⇒ a1/a2 = b1/b2 ≠ c1/c2
Hence, we can conclude that the given system of equation has no solution.
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