Question

By using remainder theorem, show that g(x) is a factor of f(x), given f(x)=x³-x²+11x+69, g(x)=x+3.
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Answer 1

Step-by-step explanation:

x+3

x=−3

p(x)=x3−x2+11x+69

p(−3)=(−3)3−(−3)2+11(−3)+69

=−27−9−33+69

=−69+69

=0

Therefore (x+3) is a factor