By using ruler and compasses only,construct an isosceles triangle ABC in which BC=5cm,AB=AC and angleBAC=90°.locate the point P such that
I)P is equidistant from the sides BC and AC
ii)P is equidistant from the points B and C
pls help me
Answers
Answered by
24
drawBC=5cm
draw angB=angC=45°
extend these lines and mark the point of intersection as A
measure angA=90°
triangle ABCis reqd triangle
now draw bisectors of ang B and angle C and mark the pt of intersection as P
measure PB=PC
draw angB=angC=45°
extend these lines and mark the point of intersection as A
measure angA=90°
triangle ABCis reqd triangle
now draw bisectors of ang B and angle C and mark the pt of intersection as P
measure PB=PC
jasleenkaur14:
hope u r satisfied with the answer
Similar questions