Question

by using suitable identities evaluate the following (103) power 3

Answer 1

(103)3 = (100 + 3)^3    [ using (a+b)³ = a³ + 3a²b + 3ab² + b³] we get

                 = 100^3 + 3*(100)^2*(3) + 3*(100)*(3)^2 + (3)^3

                 = 1000000 + 3*(10000)*(3) + 3*(100)*(9) + 27

                 = 1000000 + 90000 + 2700 + 27

                 = 1092727