by using the completing square method find the roots of the equation 4x square +4x+3
Answers
Answered by
1
4x^2+4x+3=0
=> x^2+x+3/4=0
=> x^2+x=-3/4
add (1/2)^2 both side
=> x^2+2.x (1/2) + (1/2)^2 =(-3/4)+(1/2)^2
=>(x+1/2)^2=(-2/4)
here you see left side is square term means always positive but in right side is negative term so, this quadratic equation have no real roots .
here only imaginary roots possible .
hence,
(x+1/2)^2 =(-1/2)
take square root both side
x+1/2 =+_i/root2
x= -1/2 +_i/root2
=> x^2+x+3/4=0
=> x^2+x=-3/4
add (1/2)^2 both side
=> x^2+2.x (1/2) + (1/2)^2 =(-3/4)+(1/2)^2
=>(x+1/2)^2=(-2/4)
here you see left side is square term means always positive but in right side is negative term so, this quadratic equation have no real roots .
here only imaginary roots possible .
hence,
(x+1/2)^2 =(-1/2)
take square root both side
x+1/2 =+_i/root2
x= -1/2 +_i/root2
Answered by
0
=> 4x^2 +4x +3 =0
=> 4x^2 +4x = -3
=> x^2 +x = -3/4 (dividing the whole equation by 4)
=> x^2 +x +(1/2)^2 = -3/4 +(1/2)^2
=> (x +1/2)^2 = -3/4 +1/4
=> (x +1/2)^2 = -2/4
The equation will have no real roots.
=> 4x^2 +4x = -3
=> x^2 +x = -3/4 (dividing the whole equation by 4)
=> x^2 +x +(1/2)^2 = -3/4 +(1/2)^2
=> (x +1/2)^2 = -3/4 +1/4
=> (x +1/2)^2 = -2/4
The equation will have no real roots.
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