by using the completing the square show that 4x²+3x+5 =0 has no real roots
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Sunitars123456:
In this question a=4 which is positive and D which is negative so the equation has real roots .this is solved by quadratic equation.
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-b±root(b^2-4ac)/2a
-3±root(9-4×5×4)/2×4
-3±root(9-80)/8
-3±root(-71)/8
-3±root71i/8
roots are
-3+root71i/8 ,-3-root71i/8 are roots which are not real
-3±root(9-4×5×4)/2×4
-3±root(9-80)/8
-3±root(-71)/8
-3±root71i/8
roots are
-3+root71i/8 ,-3-root71i/8 are roots which are not real
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