Question

By using the finds the amount and
compound interest of the following.
P - 6000, T-2 years and R: 19% Pia
compounded annually​

Answer 1

$\Huge\rm\blue{Solution:-}$

$\bf \red{A=(1+\dfrac{R}{100})^t}$

$\bf:\implies 6000(1+\dfrac{19}{100})^2$

$\bf:\implies 6000(\dfrac{119}{100})^2$

$\bf:\implies 6000(\dfrac{119}{100})×(\dfrac{119}{100})$

$\bf:\implies 6000(\dfrac{119}{100})×(\dfrac{119}{100})$

$\bf:\implies 6000(1.19)×(1.19)$

$\bf:\implies 6000×1.4161$

$\bf:\implies {\boxed{8496.6}}$

$\bf \red{Compound\: interest=A-P}$

$\bf :\implies{8496.6-6000}$

$\bf :\implies{\boxed{2496.6-6000}}$