by using the formula solve the equation x^2-(1+ root 2) x +root 2=0
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Answered by
6
Hey... mate here is your answer..
Given quadratic function:
y=x2−(x−2)(2x−1)
y=x2−2x2+5x−2
y=−x2+5x−2
The roots of given function will be at y=0 i.e.
−x2+5x−2=0
x2−5x+2=0
Now, using quadratic formula, the roots of above quadratic equation are given as
x1,2=−(−5)±√(−5)2−4(1)(2)2(1)
=5±√172
Thus, the roots of given quadratic function are real & distinct given as
x=5±√172
hope this is usefull to you...
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Answered by
0
Answer:
x1=-1
x2=-1.414213562
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