by using the property of real no prove that (a+b)+c=a+(b+c)
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a+b+c=RHS.
Hence proved
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Answer: Imagine that a=1 , b=2 , c=3
LHS; (a+b)+c=(1+2)+3=(3)+3=6
RHS; a+(b+c)=1+(2+3)=1+(5)=6
so , LHS=RHS
so, (a+b)+c=a+(b+c)
Step-by-step explanation:
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