by using the values of x and y from the equations x/7+y/3=5 and x/2+y/9=6 find the value of A IF 2X+3Y=A
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x/7+y/3=5
(3x+7y)/21=5
3x+7y=105 ....(i)
x/2+y/9=6
(9x+2y)/18=6
9x+2y=108 ....(ii)
now from equation (i) & (ii)
3x+7y=105 ----- x 2
9x+2y=108
9x+14y=210
9x+2y=108
- - -
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12y=92
y=92/12 = 23/3
from equation (i)
3x+7y=105
3x+7 x 23/3 = 105
3x+161/3 = 105
3x = 105-161/3
3x = (315-161)/3
3x=154/3
x = 154/9
now, 2x+ 3y = A
2 x 154/9 + 3 x 23/3 = A
A = 308/9+23
A = (308+ 207)/9
A = 515/9
A = 57.22
(3x+7y)/21=5
3x+7y=105 ....(i)
x/2+y/9=6
(9x+2y)/18=6
9x+2y=108 ....(ii)
now from equation (i) & (ii)
3x+7y=105 ----- x 2
9x+2y=108
9x+14y=210
9x+2y=108
- - -
------------------
12y=92
y=92/12 = 23/3
from equation (i)
3x+7y=105
3x+7 x 23/3 = 105
3x+161/3 = 105
3x = 105-161/3
3x = (315-161)/3
3x=154/3
x = 154/9
now, 2x+ 3y = A
2 x 154/9 + 3 x 23/3 = A
A = 308/9+23
A = (308+ 207)/9
A = 515/9
A = 57.22
prakriti27:
see if there is any mistake in calculation then let me know pls
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