By walking at 3/4th of his usual speed,a man reaches office 20 min later than usual. What is his usual time?
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Let his usual speed be x
Let his usual time be y
Let distance be z
z=x×y
z=((3/4)x)×(y+20)
x×y=(3x/4)×(y+20)
x/(3x/4)=(y+20)/y
4/3=1+(20/y)
(4/3)-1=(20/y)
1=20/y
y=20min
His usual time = 20min
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Let his usual time be y
Let distance be z
z=x×y
z=((3/4)x)×(y+20)
x×y=(3x/4)×(y+20)
x/(3x/4)=(y+20)/y
4/3=1+(20/y)
(4/3)-1=(20/y)
1=20/y
y=20min
His usual time = 20min
Hope it helps .
Plz Mark as brainliest.
Vaibhavpandey99:
this answer is wrong
how
answer may be 60
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