Question

By Walking at ¾ of his normal speed, Mike is 16 minutes late in reaching his office. The usual time taken by him to cover the distance between his home and his office is ?

a. 48 minutes
b. 60 minutes
c. 42 minutes
d. 62 minutes; By Walking at ¾ of his normal speed, Mike is 16 minutes late in reaching his office. The usual time taken by him to cover the distance between his home and his office is ?; a. 48 minutes; b. 60 minutes; c. 42 minutes; d. 62 minutes

Answer 1

{d/(3x/4)}-{d/x}=16

=>(4d-3d)/3x=16

=>d=48x

Hence, time= 48x/x=48min.

Answer 2

The usual time taken by him to cover the distance between his home and his office is 48 minutes

Solution:

By Walking at 3/4 of his normal speed, Mike is 16 minutes late in reaching his office

Therefore,

With a speed of 3/4 th of the usual speed, the time taken is 4/3 th of the usual time

(4/3 of usual time) - (usual time) = 16 minute

Let "x" be the usual time

Then,

$\frac{4}{3} \times x - x = 16 \\\\x ( \frac{4}{3} - 1) = 16 \\\\x \times \frac{1}{3} = 16\\\\x = 16 \times 3\\\\x = 48$

Thus the usual time taken by him to cover the distance between his home and his office is 48 minutes

Learn more:

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Walking 6/7th of his usual speed, a man is 12 minutes too late. the usual time taken by him to cover that distance is:

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