by what factor does kinetic energy of a moving body change if it's velocity is reduced to one third of initial velocity
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Kinetic energy= 1/2(mv^2)
if V = 1/3v
then
K.E(final) = 1/9×(initial kinetic energy)
hence final kinetic energy will reduced to 1/9th
of initial kinetic energy
if V = 1/3v
then
K.E(final) = 1/9×(initial kinetic energy)
hence final kinetic energy will reduced to 1/9th
of initial kinetic energy
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