By what factor does the kinetic energy of a moving body change, when its speed is reduced to one-third of the initial velocity?
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Kinetic energy , K= 1/2 * m * v^2 ....... (1)
when velocity is reduced by one third, new velocity = v/3
New kinetic energy , K" = 1/2 * m * (v/3)^2
= 1/2 * m* v^2 / 9
= K/9 .........( from 1)
Therefore kinetic energy reduces by a factor of 9
when velocity is reduced by one third, new velocity = v/3
New kinetic energy , K" = 1/2 * m * (v/3)^2
= 1/2 * m* v^2 / 9
= K/9 .........( from 1)
Therefore kinetic energy reduces by a factor of 9
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