Question

By what factor must [h+] be increased to increase the reduction potential of a hydrogen electrode, having fixed pressure of hydrogen gas, by 0.0282 v?

Answer 1

Explanation:

EH+/H2=E•H+/H2 -0.059/2 *log PH2/H+^2

if H+ incresed by n factor

then. change in E== 0.059/2* logn

log n =change E/0.059

0.282/0.059=0.49

~ log 3

so, n=3