Question

By what fraction does the mass of a boy increase when he starts running at a speed of 12 km h−1?

Answer 1

Answer:

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Answer 2

Explanation:

Given: The boy’s speed, $v=10 / 3 \mathrm{m} / \mathrm{s}=12 \mathrm{km} \mathrm{h}^{-1}$

The boy’s rest mass is shown as m.

The boy’s kinetic energy,

$E=12 \mathrm{mv} 2$

$\Rightarrow E=m \times 509$

Increase in the body’s energy = Boy’s kinetic energy  

When there is an increase in energy, it is converted into mass. So,

Increase in mass$=\Delta m=E c 2 \Delta m=m \times 9 \times 509 \times 1016$

Fraction increase in mass$=\Delta m m=1016 \times 5081$

$\Rightarrow \Delta \mathrm{mm}=6.17 \times 10-17$