Chemistry, asked by tdprajapati9863, 11 months ago

By what fraction does the mass of a boy increase when he starts running at a speed of 12 km h−1?

Answers

Answered by pciub85824
0

Answer:

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Answered by shilpa85475
0

Explanation:

Given: The boy’s speed, v=10 / 3 \mathrm{m} / \mathrm{s}=12 \mathrm{km} \mathrm{h}^{-1}

The boy’s rest mass is shown as m.

The boy’s kinetic energy,

E=12 \mathrm{mv} 2

\Rightarrow E=m \times 509

Increase in the body’s energy = Boy’s kinetic energy  

When there is an increase in energy, it is converted into mass. So,

Increase in mass=\Delta m=E c 2 \Delta m=m \times 9 \times 509 \times 1016

Fraction increase in mass=\Delta m m=1016 \times 5081

\Rightarrow \Delta \mathrm{mm}=6.17 \times 10-17

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