By what greatest number must 122 and 343 be divided to leave the remainder 3 in each case.
Answers
Answered by
54
122 – 2 = 120 and 243 – 3 = 240 are exactly divisible by the required number.
∴ Required number = HCF of 120 and 240 = 120
Answered by
1
Step-by-step explanation:
As we know that the largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r).
Clearly, 122 – 2 = 120 and 243 – 3 = 240 are exactly divisible by the required number.
∴ Required number = HCF of 120 and 240 = 120
Similar questions