Math, asked by kaurharishmita12345, 1 day ago

By what greatest number must 122 and 343 be divided to leave the remainder 3 in each case.​

Answers

Answered by pradhanmadhumita2021
54

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122 – 2 = 120 and 243 – 3 = 240 are exactly divisible by the required number.

∴ Required number = HCF of 120 and 240 = 120

Answered by kevinprinters2017
1

Step-by-step explanation:

As we know that the largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r).

Clearly, 122 – 2 = 120 and 243 – 3 = 240 are exactly divisible by the required number.

∴ Required number = HCF of 120 and 240 = 120

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