By what least number 3600 be divided to get a perfect cube
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Firstly , we need to find the prime factors of 3600 and group the prime factors in triplets .
3600 = 2×2×2×2×3×3×3×5
As 2 , 3 and 5 are not in triplets Therefore the required no to be divided = 2×3×3×5×5 = 450
Resulting number = 3600/450 = 8 which is 2^3.
HOPE IT HELPS
Firstly , we need to find the prime factors of 3600 and group the prime factors in triplets .
3600 = 2×2×2×2×3×3×3×5
As 2 , 3 and 5 are not in triplets Therefore the required no to be divided = 2×3×3×5×5 = 450
Resulting number = 3600/450 = 8 which is 2^3.
HOPE IT HELPS
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3
3600= 2*2*2*2*3*3*5
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